### Scribe for Wednesday

We worked on solving for the volume of a function that is revolved around the y-axis. The integral for the interval [a,b], the inner function is the length times the width times the height.

V= (2(3.141...)x)(f(x))

The height is represented by

In class, one of the examples was

V=2(pi) √(-x^3 +3x²)

When the graph is revolved around the line x=5

V=2(pi) (5-x)√(-x+3)

The second part of class was about the average value of a function. Which can be defined as:

[f(x1)+f(x2)+f(x3)+...+f(xn)]/n

dx= (b-a)/n

n=(b-a)/dx

The

The next scribe is Chris

V= (2(3.141...)x)(f(x))

The height is represented by

**f(x),**the width is**dx,**the length is**2(pi)x**.In class, one of the examples was

**f(x)=√(-x+3)**V=2(pi) √(-x^3 +3x²)

When the graph is revolved around the line x=5

V=2(pi) (5-x)√(-x+3)

The second part of class was about the average value of a function. Which can be defined as:

[f(x1)+f(x2)+f(x3)+...+f(xn)]/n

dx= (b-a)/n

n=(b-a)/dx

**1/(b-a)****f(x)**The

**Average Value of a Function**is defined by the previous expression. This expression can be used to find the mean value or f(c).The next scribe is Chris

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