Related rates of change
I can image how hard the exam will be, we need to do a lot of exercise to be comfortable when we white that exam which will be on May.
There were three questions on the white board. It was about related rates of change.
Air is blown into a spherical balloon at a rate of 12In^3/ sec. How fast is the radius increasing at the instant the diameter is 1 foot.
From the question that we know the rate of change volume dV/dt=12
1 foot is equal to 12 inch. So, the radius is 6 inch.
And the question is to find the rate of change radius dr/dt.
Volume of Sphere formula: V=4/3 pai r^3
Up to here, we know to fine the rate of change; we need to find the derivative of the function.
According to the Product and chain role:
dV/dt = 4/3pai* 3 r^2 (dr/dt)
dV/dt = 4 pai r^2 dr/dt
12 = 4 pai 6^2 dr/dt
Two questions left, we didn’t have enough time to finish it. And the homework will be on the Bolg tonight.
Nest Scribe is Steve:P